y^2+yt+12t^2=

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Solution for y^2+yt+12t^2= equation:


Simplifying
y2 + yt + 12t2 = 0

Reorder the terms:
ty + 12t2 + y2 = 0

Solving
ty + 12t2 + y2 = 0

Solving for variable 't'.

Begin completing the square.  Divide all terms by
12 the coefficient of the squared term: 

Divide each side by '12'.
0.08333333333ty + t2 + 0.08333333333y2 = 0

Move the constant term to the right:

Add '-1y2' to each side of the equation.
0.08333333333ty + t2 + 0.08333333333y2 + -1y2 = 0 + -1y2

Combine like terms: 0.08333333333y2 + -1y2 = -0.91666666667y2
0.08333333333ty + t2 + -0.91666666667y2 = 0 + -1y2
Remove the zero:
0.08333333333ty + t2 + -0.91666666667y2 = -1y2

The t term is ty.  Take half its coefficient (0.5y).
Square it (0.25y2) and add it to both sides.

Add '0.25y2' to each side of the equation.
0.08333333333ty + t2 + -0.91666666667y2 + 0.25y2 = -1y2 + 0.25y2

Combine like terms: -0.91666666667y2 + 0.25y2 = -0.66666666667y2
0.08333333333ty + t2 + -0.66666666667y2 = -1y2 + 0.25y2

Combine like terms: -1y2 + 0.25y2 = -0.75y2
0.08333333333ty + t2 + -0.66666666667y2 = -0.75y2

Factor a perfect square on the left side:
(t + 0.5y)(t + 0.5y) = -0.75y2

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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